1540125201301 has 4 divisors (see below), whose sum is σ = 1563112144672. Its totient is φ = 1517138257932.

The previous prime is 1540125201257. The next prime is 1540125201319. The reversal of 1540125201301 is 1031025210451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1540125201301 - 2¹¹ = 1540125199253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1540125231301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11493471585 + ... + 11493471718.

It is an arithmetic number, because the mean of its divisors is an integer number (390778036168).

Almost surely, 2^{1540125201301} is an apocalyptic number.

It is an amenable number.

1540125201301 is a deficient number, since it is larger than the sum of its proper divisors (22986943371).

1540125201301 is an equidigital number, since it uses as much as digits as its factorization.

1540125201301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22986943370.

The product of its (nonzero) digits is 1200, while the sum is 25.

The spelling of 1540125201301 in words is "one trillion, five hundred forty billion, one hundred twenty-five million, two hundred one thousand, three hundred one".