15401540041231 has 4 divisors (see below), whose sum is σ = 15654024304264. Its totient is φ = 15149055778200.

The previous prime is 15401540041193. The next prime is 15401540041247. The reversal of 15401540041231 is 13214004510451.

15401540041231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15401540041231 - 2⁷ = 15401540041103 is a prime.

It is a super-2 number, since 2×15401540041231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15401540041193 and 15401540041202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15401540741231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126242131425 + ... + 126242131546.

It is an arithmetic number, because the mean of its divisors is an integer number (3913506076066).

Almost surely, 2^{15401540041231} is an apocalyptic number.

15401540041231 is a deficient number, since it is larger than the sum of its proper divisors (252484263033).

15401540041231 is an equidigital number, since it uses as much as digits as its factorization.

15401540041231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252484263032.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 15401540041231 its reverse (13214004510451), we get a palindrome (28615544551682).

The spelling of 15401540041231 in words is "fifteen trillion, four hundred one billion, five hundred forty million, forty-one thousand, two hundred thirty-one".