Base | Representation |
---|---|
bin | 1000111101111001101… |
… | …1001001010101010111 |
3 | 112201122101121221102201 |
4 | 2033132123021111113 |
5 | 10011001202412211 |
6 | 154434440145331 |
7 | 14062432154401 |
oct | 2173633112527 |
9 | 481571557381 |
10 | 154055513431 |
11 | 5a375359446 |
12 | 25a34a68247 |
13 | 116b1839951 |
14 | 7656235b71 |
15 | 4019b6d0c1 |
hex | 23de6c9557 |
154055513431 has 2 divisors, whose sum is σ = 154055513432. Its totient is φ = 154055513430.
The previous prime is 154055513411. The next prime is 154055513449. The reversal of 154055513431 is 134315550451.
It is a strong prime.
It is an emirp because it is prime and its reverse (134315550451) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 154055513431 - 27 = 154055513303 is a prime.
It is a super-2 number, since 2×1540555134312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (154055513401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77027756715 + 77027756716.
It is an arithmetic number, because the mean of its divisors is an integer number (77027756716).
Almost surely, 2154055513431 is an apocalyptic number.
154055513431 is a deficient number, since it is larger than the sum of its proper divisors (1).
154055513431 is an equidigital number, since it uses as much as digits as its factorization.
154055513431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 154055513431 in words is "one hundred fifty-four billion, fifty-five million, five hundred thirteen thousand, four hundred thirty-one".
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