Base | Representation |
---|---|
bin | 10110011011001100001… |
… | …000010110000000011011 |
3 | 12110022122112201001101001 |
4 | 112123030020112000123 |
5 | 200222003344000243 |
6 | 3135534115405431 |
7 | 216222662432656 |
oct | 26331410260033 |
9 | 5408575631331 |
10 | 1541023031323 |
11 | 5445a9365a66 |
12 | 20a7b15b3877 |
13 | b241940b139 |
14 | 5482ba5c89d |
15 | 2a143ab1a4d |
hex | 166cc21601b |
1541023031323 has 2 divisors, whose sum is σ = 1541023031324. Its totient is φ = 1541023031322.
The previous prime is 1541023031297. The next prime is 1541023031341. The reversal of 1541023031323 is 3231303201451.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1541023031323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1541023031291 and 1541023031300.
It is not a weakly prime, because it can be changed into another prime (1541023031393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770511515661 + 770511515662.
It is an arithmetic number, because the mean of its divisors is an integer number (770511515662).
Almost surely, 21541023031323 is an apocalyptic number.
1541023031323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541023031323 is an equidigital number, since it uses as much as digits as its factorization.
1541023031323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 1541023031323 its reverse (3231303201451), we get a palindrome (4772326232774).
The spelling of 1541023031323 in words is "one trillion, five hundred forty-one billion, twenty-three million, thirty-one thousand, three hundred twenty-three".
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