Base | Representation |
---|---|
bin | 10110011011010001000… |
… | …011000011101000000001 |
3 | 12110022212021221111012012 |
4 | 112123101003003220001 |
5 | 200222141004001033 |
6 | 3135550223542305 |
7 | 216225013610651 |
oct | 26332103035001 |
9 | 5408767844165 |
10 | 1541105531393 |
11 | 54464099453a |
12 | 20a81515a995 |
13 | b243053544c |
14 | 548389b6361 |
15 | 2a14ae5b248 |
hex | 166d10c3a01 |
1541105531393 has 2 divisors, whose sum is σ = 1541105531394. Its totient is φ = 1541105531392.
The previous prime is 1541105531389. The next prime is 1541105531437. The reversal of 1541105531393 is 3931355011451.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1207816386049 + 333289145344 = 1099007^2 + 577312^2 .
It is a cyclic number.
It is not a de Polignac number, because 1541105531393 - 22 = 1541105531389 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1541105531393.
It is not a weakly prime, because it can be changed into another prime (1541105531093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770552765696 + 770552765697.
It is an arithmetic number, because the mean of its divisors is an integer number (770552765697).
Almost surely, 21541105531393 is an apocalyptic number.
It is an amenable number.
1541105531393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541105531393 is an equidigital number, since it uses as much as digits as its factorization.
1541105531393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 41.
The spelling of 1541105531393 in words is "one trillion, five hundred forty-one billion, one hundred five million, five hundred thirty-one thousand, three hundred ninety-three".
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