Base | Representation |
---|---|
bin | 11100101101011000… |
… | …01000111010011011 |
3 | 1110210011101022210202 |
4 | 32112230020322123 |
5 | 223031220231011 |
6 | 11025231132415 |
7 | 1053643543535 |
oct | 162654107233 |
9 | 43704338722 |
10 | 15413055131 |
11 | 659a2a44a1 |
12 | 2ba197410b |
13 | 15b82ab986 |
14 | a63026855 |
15 | 60320623b |
hex | 396b08e9b |
15413055131 has 2 divisors, whose sum is σ = 15413055132. Its totient is φ = 15413055130.
The previous prime is 15413055103. The next prime is 15413055143. The reversal of 15413055131 is 13155031451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15413055131 - 226 = 15345946267 is a prime.
It is a super-2 number, since 2×154130551312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15413055094 and 15413055103.
It is not a weakly prime, because it can be changed into another prime (15413055101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7706527565 + 7706527566.
It is an arithmetic number, because the mean of its divisors is an integer number (7706527566).
Almost surely, 215413055131 is an apocalyptic number.
15413055131 is a deficient number, since it is larger than the sum of its proper divisors (1).
15413055131 is an equidigital number, since it uses as much as digits as its factorization.
15413055131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 15413055131 its reverse (13155031451), we get a palindrome (28568086582).
The spelling of 15413055131 in words is "fifteen billion, four hundred thirteen million, fifty-five thousand, one hundred thirty-one".
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