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154136523260513 is a prime number
BaseRepresentation
bin100011000010111110110100…
…101101110100001001100001
3202012202022022022202201010202
4203002332310231310021201
5130200333044423314023
61303453201413234545
744315665510265213
oct4302766455641141
9665668268681122
10154136523260513
1145126a29060152
1215354835932a55
13680101cb42521
142a0c3673225b3
1512c46a0c96128
hex8c2fb4b74261

154136523260513 has 2 divisors, whose sum is σ = 154136523260514. Its totient is φ = 154136523260512.

The previous prime is 154136523260399. The next prime is 154136523260549. The reversal of 154136523260513 is 315062325631451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139721076014689 + 14415447245824 = 11820367^2 + 3796768^2 .

It is a cyclic number.

It is not a de Polignac number, because 154136523260513 - 222 = 154136519066209 is a prime.

It is not a weakly prime, because it can be changed into another prime (154136523260563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77068261630256 + 77068261630257.

It is an arithmetic number, because the mean of its divisors is an integer number (77068261630257).

Almost surely, 2154136523260513 is an apocalyptic number.

It is an amenable number.

154136523260513 is a deficient number, since it is larger than the sum of its proper divisors (1).

154136523260513 is an equidigital number, since it uses as much as digits as its factorization.

154136523260513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944000, while the sum is 47.

Adding to 154136523260513 its reverse (315062325631451), we get a palindrome (469198848891964).

The spelling of 154136523260513 in words is "one hundred fifty-four trillion, one hundred thirty-six billion, five hundred twenty-three million, two hundred sixty thousand, five hundred thirteen".