Base | Representation |
---|---|
bin | 100011000011000010010000… |
… | …100110100010100101101111 |
3 | 202012202122211102102102100012 |
4 | 203003002100212202211233 |
5 | 130200413123324403403 |
6 | 1303455011435123435 |
7 | 44316156104043212 |
oct | 4303022046424557 |
9 | 665678742372305 |
10 | 154140212341103 |
11 | 45128551491a8a |
12 | 153554a52a357b |
13 | 680148a211c51 |
14 | 2a0c5d725d779 |
15 | 12c4819aa1ed8 |
hex | 8c30909a296f |
154140212341103 has 2 divisors, whose sum is σ = 154140212341104. Its totient is φ = 154140212341102.
The previous prime is 154140212340977. The next prime is 154140212341117. The reversal of 154140212341103 is 301143212041451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 154140212341103 - 220 = 154140211292527 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 154140212341103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (154140212341153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77070106170551 + 77070106170552.
It is an arithmetic number, because the mean of its divisors is an integer number (77070106170552).
Almost surely, 2154140212341103 is an apocalyptic number.
154140212341103 is a deficient number, since it is larger than the sum of its proper divisors (1).
154140212341103 is an equidigital number, since it uses as much as digits as its factorization.
154140212341103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 154140212341103 its reverse (301143212041451), we get a palindrome (455283424382554).
The spelling of 154140212341103 in words is "one hundred fifty-four trillion, one hundred forty billion, two hundred twelve million, three hundred forty-one thousand, one hundred three".
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