Base | Representation |
---|---|
bin | 1110000001001111100111… |
… | …0101001101101010011111 |
3 | 2000120121121101110021111121 |
4 | 3200103321311031222133 |
5 | 4010022431214300211 |
6 | 52441201134431411 |
7 | 3150443345201305 |
oct | 340237165155237 |
9 | 60517541407447 |
10 | 15414534134431 |
11 | 4a032a3732223 |
12 | 188b534362567 |
13 | 87a779a13863 |
14 | 3b40d3070275 |
15 | 1bae79eed271 |
hex | e04f9d4da9f |
15414534134431 has 2 divisors, whose sum is σ = 15414534134432. Its totient is φ = 15414534134430.
The previous prime is 15414534134401. The next prime is 15414534134501. The reversal of 15414534134431 is 13443143541451.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15414534134431 - 27 = 15414534134303 is a prime.
It is a super-2 number, since 2×154145341344312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15414534134401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7707267067215 + 7707267067216.
It is an arithmetic number, because the mean of its divisors is an integer number (7707267067216).
Almost surely, 215414534134431 is an apocalyptic number.
15414534134431 is a deficient number, since it is larger than the sum of its proper divisors (1).
15414534134431 is an equidigital number, since it uses as much as digits as its factorization.
15414534134431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 43.
Adding to 15414534134431 its reverse (13443143541451), we get a palindrome (28857677675882).
The spelling of 15414534134431 in words is "fifteen trillion, four hundred fourteen billion, five hundred thirty-four million, one hundred thirty-four thousand, four hundred thirty-one".
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