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15421311413 is a prime number
BaseRepresentation
bin11100101110010111…
…01000100110110101
31110210201220210021222
432113023220212311
5223040323431123
611030124120125
71054103661404
oct162713504665
943721823258
1015421311413
1165a3a23572
122ba4696045
1315b9c0c951
14a6417563b
15603cd76c8
hex3972e89b5

15421311413 has 2 divisors, whose sum is σ = 15421311414. Its totient is φ = 15421311412.

The previous prime is 15421311401. The next prime is 15421311419. The reversal of 15421311413 is 31411312451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14019033604 + 1402277809 = 118402^2 + 37447^2 .

It is a cyclic number.

It is not a de Polignac number, because 15421311413 - 24 = 15421311397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15421311419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7710655706 + 7710655707.

It is an arithmetic number, because the mean of its divisors is an integer number (7710655707).

Almost surely, 215421311413 is an apocalyptic number.

It is an amenable number.

15421311413 is a deficient number, since it is larger than the sum of its proper divisors (1).

15421311413 is an equidigital number, since it uses as much as digits as its factorization.

15421311413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 26.

Adding to 15421311413 its reverse (31411312451), we get a palindrome (46832623864).

The spelling of 15421311413 in words is "fifteen billion, four hundred twenty-one million, three hundred eleven thousand, four hundred thirteen".