Base | Representation |
---|---|
bin | 1000111110100110011… |
… | …0111001000111100101 |
3 | 112202010110200110121022 |
4 | 2033221212321013211 |
5 | 10011342221021432 |
6 | 154505221500525 |
7 | 14100201034661 |
oct | 2175146710745 |
9 | 482113613538 |
10 | 154243142117 |
11 | 5a461261679 |
12 | 25a87871745 |
13 | 11711681c3c |
14 | 76731178a1 |
15 | 402b381b12 |
hex | 23e99b91e5 |
154243142117 has 2 divisors, whose sum is σ = 154243142118. Its totient is φ = 154243142116.
The previous prime is 154243142101. The next prime is 154243142143. The reversal of 154243142117 is 711241342451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 154233711076 + 9431041 = 392726^2 + 3071^2 .
It is a cyclic number.
It is not a de Polignac number, because 154243142117 - 24 = 154243142101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (154243142177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77121571058 + 77121571059.
It is an arithmetic number, because the mean of its divisors is an integer number (77121571059).
Almost surely, 2154243142117 is an apocalyptic number.
It is an amenable number.
154243142117 is a deficient number, since it is larger than the sum of its proper divisors (1).
154243142117 is an equidigital number, since it uses as much as digits as its factorization.
154243142117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26880, while the sum is 35.
Adding to 154243142117 its reverse (711241342451), we get a palindrome (865484484568).
The spelling of 154243142117 in words is "one hundred fifty-four billion, two hundred forty-three million, one hundred forty-two thousand, one hundred seventeen".
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