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154243142117 is a prime number
BaseRepresentation
bin1000111110100110011…
…0111001000111100101
3112202010110200110121022
42033221212321013211
510011342221021432
6154505221500525
714100201034661
oct2175146710745
9482113613538
10154243142117
115a461261679
1225a87871745
1311711681c3c
1476731178a1
15402b381b12
hex23e99b91e5

154243142117 has 2 divisors, whose sum is σ = 154243142118. Its totient is φ = 154243142116.

The previous prime is 154243142101. The next prime is 154243142143. The reversal of 154243142117 is 711241342451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154233711076 + 9431041 = 392726^2 + 3071^2 .

It is a cyclic number.

It is not a de Polignac number, because 154243142117 - 24 = 154243142101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154243142177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77121571058 + 77121571059.

It is an arithmetic number, because the mean of its divisors is an integer number (77121571059).

Almost surely, 2154243142117 is an apocalyptic number.

It is an amenable number.

154243142117 is a deficient number, since it is larger than the sum of its proper divisors (1).

154243142117 is an equidigital number, since it uses as much as digits as its factorization.

154243142117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 26880, while the sum is 35.

Adding to 154243142117 its reverse (711241342451), we get a palindrome (865484484568).

The spelling of 154243142117 in words is "one hundred fifty-four billion, two hundred forty-three million, one hundred forty-two thousand, one hundred seventeen".