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15432512131 is a prime number
BaseRepresentation
bin11100101111101100…
…10111001010000011
31110211111222211210101
432113312113022003
5223101210342011
611031204143231
71054301121511
oct162766271203
943744884711
1015432512131
1165aa283863
122ba8397b17
1315bc331baa
14a6584d4b1
15604c9b2c1
hex397d97283

15432512131 has 2 divisors, whose sum is σ = 15432512132. Its totient is φ = 15432512130.

The previous prime is 15432512129. The next prime is 15432512189. The reversal of 15432512131 is 13121523451.

It is a weak prime.

It is an emirp because it is prime and its reverse (13121523451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15432512131 - 21 = 15432512129 is a prime.

It is a super-3 number, since 3×154325121313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 15432512129, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 15432512131.

It is not a weakly prime, because it can be changed into another prime (15432512191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7716256065 + 7716256066.

It is an arithmetic number, because the mean of its divisors is an integer number (7716256066).

Almost surely, 215432512131 is an apocalyptic number.

15432512131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15432512131 is an equidigital number, since it uses as much as digits as its factorization.

15432512131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3600, while the sum is 28.

The spelling of 15432512131 in words is "fifteen billion, four hundred thirty-two million, five hundred twelve thousand, one hundred thirty-one".