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1543345484137 is a prime number
BaseRepresentation
bin10110011101010110100…
…011110011000101101001
312110112122101210212200221
4112131112203303011221
5200241232420443022
63141000401530041
7216334353110302
oct26352643630551
95415571725627
101543345484137
11545590322156
1220b13b343921
13b26c9614c82
14549ac2937a9
152a22c91acc7
hex167568f3169

1543345484137 has 2 divisors, whose sum is σ = 1543345484138. Its totient is φ = 1543345484136.

The previous prime is 1543345484063. The next prime is 1543345484189. The reversal of 1543345484137 is 7314845433451.

It is an a-pointer prime, because the next prime (1543345484189) can be obtained adding 1543345484137 to its sum of digits (52).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1226133221481 + 317212262656 = 1107309^2 + 563216^2 .

It is a cyclic number.

It is not a de Polignac number, because 1543345484137 - 223 = 1543337095529 is a prime.

It is not a weakly prime, because it can be changed into another prime (1543345464137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771672742068 + 771672742069.

It is an arithmetic number, because the mean of its divisors is an integer number (771672742069).

Almost surely, 21543345484137 is an apocalyptic number.

It is an amenable number.

1543345484137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1543345484137 is an equidigital number, since it uses as much as digits as its factorization.

1543345484137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9676800, while the sum is 52.

The spelling of 1543345484137 in words is "one trillion, five hundred forty-three billion, three hundred forty-five million, four hundred eighty-four thousand, one hundred thirty-seven".