Base | Representation |
---|---|
bin | 10110011101100010001… |
… | …110011100110010000111 |
3 | 12110120011001010000001211 |
4 | 112131202032130302013 |
5 | 200242133022324333 |
6 | 3141032033032251 |
7 | 216342250562302 |
oct | 26354216346207 |
9 | 5416131100054 |
10 | 1543541214343 |
11 | 545680859157 |
12 | 20b1949b5687 |
13 | b272b03596b |
14 | 549ca283b39 |
15 | 2a23ebceecd |
hex | 1676239cc87 |
1543541214343 has 2 divisors, whose sum is σ = 1543541214344. Its totient is φ = 1543541214342.
The previous prime is 1543541214307. The next prime is 1543541214359. The reversal of 1543541214343 is 3434121453451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1543541214343 - 221 = 1543539117191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1543541214296 and 1543541214305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1543541214143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771770607171 + 771770607172.
It is an arithmetic number, because the mean of its divisors is an integer number (771770607172).
Almost surely, 21543541214343 is an apocalyptic number.
1543541214343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1543541214343 is an equidigital number, since it uses as much as digits as its factorization.
1543541214343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 345600, while the sum is 40.
Adding to 1543541214343 its reverse (3434121453451), we get a palindrome (4977662667794).
The spelling of 1543541214343 in words is "one trillion, five hundred forty-three billion, five hundred forty-one million, two hundred fourteen thousand, three hundred forty-three".
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