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154492471213 is a prime number
BaseRepresentation
bin1000111111100001111…
…0000000011110101101
3112202202211211200211021
42033320132000132231
510012400033034323
6154550045454141
714106316223653
oct2177036003655
9482684750737
10154492471213
115a579a77283
1225b37271351
131175121b152
14769829add3
1540431d205d
hex23f87807ad

154492471213 has 2 divisors, whose sum is σ = 154492471214. Its totient is φ = 154492471212.

The previous prime is 154492471201. The next prime is 154492471219. The reversal of 154492471213 is 312174294451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90290033289 + 64202437924 = 300483^2 + 253382^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154492471213 is a prime.

It is a super-2 number, since 2×1544924712132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 154492471213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154492471219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77246235606 + 77246235607.

It is an arithmetic number, because the mean of its divisors is an integer number (77246235607).

Almost surely, 2154492471213 is an apocalyptic number.

It is an amenable number.

154492471213 is a deficient number, since it is larger than the sum of its proper divisors (1).

154492471213 is an equidigital number, since it uses as much as digits as its factorization.

154492471213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 241920, while the sum is 43.

The spelling of 154492471213 in words is "one hundred fifty-four billion, four hundred ninety-two million, four hundred seventy-one thousand, two hundred thirteen".