Base | Representation |
---|---|
bin | 11100110011011110… |
… | …11010001001100101 |
3 | 1110220201200222110212 |
4 | 32121233122021211 |
5 | 223132321300223 |
6 | 11034300225205 |
7 | 1055134621634 |
oct | 163157321145 |
9 | 43821628425 |
10 | 15464243813 |
11 | 6616187297 |
12 | 2bb6b3b205 |
13 | 15c5a92135 |
14 | a69b4d51b |
15 | 607968278 |
hex | 399bda265 |
15464243813 has 2 divisors, whose sum is σ = 15464243814. Its totient is φ = 15464243812.
The previous prime is 15464243771. The next prime is 15464243831. The reversal of 15464243813 is 31834246451.
Together with next prime (15464243831) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14319233569 + 1145010244 = 119663^2 + 33838^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15464243813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15464243833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7732121906 + 7732121907.
It is an arithmetic number, because the mean of its divisors is an integer number (7732121907).
Almost surely, 215464243813 is an apocalyptic number.
It is an amenable number.
15464243813 is a deficient number, since it is larger than the sum of its proper divisors (1).
15464243813 is an equidigital number, since it uses as much as digits as its factorization.
15464243813 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 276480, while the sum is 41.
The spelling of 15464243813 in words is "fifteen billion, four hundred sixty-four million, two hundred forty-three thousand, eight hundred thirteen".
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