Base | Representation |
---|---|
bin | 1001000001011011010… |
… | …0010101100010011001 |
3 | 112211002022221012121201 |
4 | 2100112310111202121 |
5 | 10014420410003423 |
6 | 155112355034201 |
7 | 14125041132214 |
oct | 2202664254231 |
9 | 484068835551 |
10 | 155001641113 |
11 | 5a810427150 |
12 | 2605989b961 |
13 | 11802864007 |
14 | 7705b5c77b |
15 | 4072c5c2ad |
hex | 2416d15899 |
155001641113 has 4 divisors (see below), whose sum is σ = 169092699408. Its totient is φ = 140910582820.
The previous prime is 155001641089. The next prime is 155001641129. The reversal of 155001641113 is 311146100551.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 155001641113 - 29 = 155001640601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (155001641213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7045529131 + ... + 7045529152.
It is an arithmetic number, because the mean of its divisors is an integer number (42273174852).
Almost surely, 2155001641113 is an apocalyptic number.
It is an amenable number.
155001641113 is a deficient number, since it is larger than the sum of its proper divisors (14091058295).
155001641113 is a wasteful number, since it uses less digits than its factorization.
155001641113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14091058294.
The product of its (nonzero) digits is 1800, while the sum is 28.
Adding to 155001641113 its reverse (311146100551), we get a palindrome (466147741664).
The spelling of 155001641113 in words is "one hundred fifty-five billion, one million, six hundred forty-one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •