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155001641113 = 1114091058283
BaseRepresentation
bin1001000001011011010…
…0010101100010011001
3112211002022221012121201
42100112310111202121
510014420410003423
6155112355034201
714125041132214
oct2202664254231
9484068835551
10155001641113
115a810427150
122605989b961
1311802864007
147705b5c77b
154072c5c2ad
hex2416d15899

155001641113 has 4 divisors (see below), whose sum is σ = 169092699408. Its totient is φ = 140910582820.

The previous prime is 155001641089. The next prime is 155001641129. The reversal of 155001641113 is 311146100551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 155001641113 - 29 = 155001640601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (155001641213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7045529131 + ... + 7045529152.

It is an arithmetic number, because the mean of its divisors is an integer number (42273174852).

Almost surely, 2155001641113 is an apocalyptic number.

It is an amenable number.

155001641113 is a deficient number, since it is larger than the sum of its proper divisors (14091058295).

155001641113 is a wasteful number, since it uses less digits than its factorization.

155001641113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14091058294.

The product of its (nonzero) digits is 1800, while the sum is 28.

Adding to 155001641113 its reverse (311146100551), we get a palindrome (466147741664).

The spelling of 155001641113 in words is "one hundred fifty-five billion, one million, six hundred forty-one thousand, one hundred thirteen".

Divisors: 1 11 14091058283 155001641113