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1550104431413 is a prime number
BaseRepresentation
bin10110100011101001011…
…011001000101100110101
312111012002102221222022112
4112203221123020230311
5200344103213301123
63144035205340405
7216664014161036
oct26435133105465
95435072858275
101550104431413
115484395a429a
12210506a07705
13b32359bbb65
145504dbc2a8d
152a4c5ebbd78
hex168e96c8b35

1550104431413 has 2 divisors, whose sum is σ = 1550104431414. Its totient is φ = 1550104431412.

The previous prime is 1550104431277. The next prime is 1550104431439. The reversal of 1550104431413 is 3141344010551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 920078068849 + 630026362564 = 959207^2 + 793742^2 .

It is a cyclic number.

It is not a de Polignac number, because 1550104431413 - 220 = 1550103382837 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1550104431413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1550104439413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775052215706 + 775052215707.

It is an arithmetic number, because the mean of its divisors is an integer number (775052215707).

Almost surely, 21550104431413 is an apocalyptic number.

It is an amenable number.

1550104431413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1550104431413 is an equidigital number, since it uses as much as digits as its factorization.

1550104431413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1550104431413 its reverse (3141344010551), we get a palindrome (4691448441964).

The spelling of 1550104431413 in words is "one trillion, five hundred fifty billion, one hundred four million, four hundred thirty-one thousand, four hundred thirteen".