Base | Representation |
---|---|
bin | 10110100011111011010… |
… | …010011001011001101011 |
3 | 12111012212022220021001102 |
4 | 112203323102121121223 |
5 | 200400211424133121 |
6 | 3144125033112015 |
7 | 220004313445043 |
oct | 26437322313153 |
9 | 5435768807042 |
10 | 1550404130411 |
11 | 548582792614 |
12 | 21058b25860b |
13 | b3282b12946 |
14 | 5507b918723 |
15 | 2a4e246b90b |
hex | 168fb49966b |
1550404130411 has 2 divisors, whose sum is σ = 1550404130412. Its totient is φ = 1550404130410.
The previous prime is 1550404130393. The next prime is 1550404130417. The reversal of 1550404130411 is 1140314040551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1550404130411 - 210 = 1550404129387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1550404130417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775202065205 + 775202065206.
It is an arithmetic number, because the mean of its divisors is an integer number (775202065206).
Almost surely, 21550404130411 is an apocalyptic number.
1550404130411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1550404130411 is an equidigital number, since it uses as much as digits as its factorization.
1550404130411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 1550404130411 its reverse (1140314040551), we get a palindrome (2690718170962).
The spelling of 1550404130411 in words is "one trillion, five hundred fifty billion, four hundred four million, one hundred thirty thousand, four hundred eleven".
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