Base | Representation |
---|---|
bin | 100011010000010001111100… |
… | …010011111111100010001011 |
3 | 202022222200012022111021212210 |
4 | 203100101330103333202023 |
5 | 130310321212140020410 |
6 | 1305433101150440203 |
7 | 44442010402023333 |
oct | 4320217423774213 |
9 | 668880168437783 |
10 | 155050405001355 |
11 | 45449564516336 |
12 | 15481982b03063 |
13 | 6869262572a66 |
14 | 2a406a01da0c3 |
15 | 12dd33bd46220 |
hex | 8d047c4ff88b |
155050405001355 has 64 divisors (see below), whose sum is σ = 258305643380736. Its totient is φ = 79351559040000.
The previous prime is 155050405001341. The next prime is 155050405001381. The reversal of 155050405001355 is 553100504050551.
155050405001355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 155050405001355 - 230 = 155049331259531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2023933462 + ... + 2024010068.
It is an arithmetic number, because the mean of its divisors is an integer number (4036025677824).
Almost surely, 2155050405001355 is an apocalyptic number.
155050405001355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
155050405001355 is a deficient number, since it is larger than the sum of its proper divisors (103255238379381).
155050405001355 is a wasteful number, since it uses less digits than its factorization.
155050405001355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130668.
The product of its (nonzero) digits is 187500, while the sum is 39.
The spelling of 155050405001355 in words is "one hundred fifty-five trillion, fifty billion, four hundred five million, one thousand, three hundred fifty-five".
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