Base | Representation |
---|---|
bin | 1110000110100000110100… |
… | …1000010111010000000011 |
3 | 2000220021020202020012122211 |
4 | 3201220031020113100003 |
5 | 4013013321333003010 |
6 | 52550531143442551 |
7 | 3160126435306366 |
oct | 341501510272003 |
9 | 60807222205584 |
10 | 15505052234755 |
11 | 4a387238527a6 |
12 | 18a4b96756457 |
13 | 886173c87775 |
14 | 3b863cab60dd |
15 | 1bd4c6abb08a |
hex | e1a0d217403 |
15505052234755 has 32 divisors (see below), whose sum is σ = 18846611236800. Its totient is φ = 12244602273792.
The previous prime is 15505052234747. The next prime is 15505052234843. The reversal of 15505052234755 is 55743225050551.
It is a cyclic number.
It is not a de Polignac number, because 15505052234755 - 23 = 15505052234747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15505052234699 and 15505052234708.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 384825651 + ... + 384865939.
It is an arithmetic number, because the mean of its divisors is an integer number (588956601150).
Almost surely, 215505052234755 is an apocalyptic number.
15505052234755 is a deficient number, since it is larger than the sum of its proper divisors (3341559002045).
15505052234755 is a wasteful number, since it uses less digits than its factorization.
15505052234755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43143.
The product of its (nonzero) digits is 5250000, while the sum is 49.
The spelling of 15505052234755 in words is "fifteen trillion, five hundred five billion, fifty-two million, two hundred thirty-four thousand, seven hundred fifty-five".
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