Base | Representation |
---|---|
bin | 100011010000010101011001… |
… | …100000110011011001100111 |
3 | 202100000000202221121212110101 |
4 | 203100111121200303121213 |
5 | 130310401312211434023 |
6 | 1305434513321004531 |
7 | 44442201354034546 |
oct | 4320253140633147 |
9 | 670000687555411 |
10 | 155054116124263 |
11 | 45450099332964 |
12 | 15482639923747 |
13 | 686970438c385 |
14 | 2a4093303415d |
15 | 12dd4a7a581ad |
hex | 8d0559833667 |
155054116124263 has 2 divisors, whose sum is σ = 155054116124264. Its totient is φ = 155054116124262.
The previous prime is 155054116124249. The next prime is 155054116124339. The reversal of 155054116124263 is 362421611450551.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-155054116124263 is a prime.
It is a super-3 number, since 3×1550541161242633 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155054116124203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77527058062131 + 77527058062132.
It is an arithmetic number, because the mean of its divisors is an integer number (77527058062132).
Almost surely, 2155054116124263 is an apocalyptic number.
155054116124263 is a deficient number, since it is larger than the sum of its proper divisors (1).
155054116124263 is an equidigital number, since it uses as much as digits as its factorization.
155054116124263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 46.
The spelling of 155054116124263 in words is "one hundred fifty-five trillion, fifty-four billion, one hundred sixteen million, one hundred twenty-four thousand, two hundred sixty-three".
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