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155114022340111 = 801911934307121
BaseRepresentation
bin100011010001001101001100…
…001100111000011000001111
3202100012202101220201221112111
4203101031030030320120033
5130312342004204340421
61305522221555044451
744446422034336222
oct4321151414703017
9670182356657474
10155114022340111
114547353a88455a
12154921782a0727
136872260571083
142a437b72735b9
1512ded11e32ee1
hex8d134c33860f

155114022340111 has 4 divisors (see below), whose sum is σ = 155115956727424. Its totient is φ = 155112087952800.

The previous prime is 155114022340099. The next prime is 155114022340171. The reversal of 155114022340111 is 111043220411551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 155114022340111 - 211 = 155114022338063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155114022340171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 967073370 + ... + 967233751.

It is an arithmetic number, because the mean of its divisors is an integer number (38778989181856).

Almost surely, 2155114022340111 is an apocalyptic number.

155114022340111 is a deficient number, since it is larger than the sum of its proper divisors (1934387313).

155114022340111 is an equidigital number, since it uses as much as digits as its factorization.

155114022340111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1934387312.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 155114022340111 its reverse (111043220411551), we get a palindrome (266157242751662).

The spelling of 155114022340111 in words is "one hundred fifty-five trillion, one hundred fourteen billion, twenty-two million, three hundred forty thousand, one hundred eleven".

Divisors: 1 80191 1934307121 155114022340111