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155144401230113 is a prime number
BaseRepresentation
bin100011010001101001011110…
…111011001001100100100001
3202100022122211001222110021122
4203101221132323021210201
5130313341213203330423
61305544204244102025
744451545614545521
oct4321513673114441
9670278731873248
10155144401230113
1145485409985219
1215498036094915
136875092296029
142a45059b49681
1512e09dde508c8
hex8d1a5eec9921

155144401230113 has 2 divisors, whose sum is σ = 155144401230114. Its totient is φ = 155144401230112.

The previous prime is 155144401230083. The next prime is 155144401230199. The reversal of 155144401230113 is 311032104441551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129785592953104 + 25358808277009 = 11392348^2 + 5035753^2 .

It is a cyclic number.

It is not a de Polignac number, because 155144401230113 - 222 = 155144397035809 is a prime.

It is not a weakly prime, because it can be changed into another prime (155144401232113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77572200615056 + 77572200615057.

It is an arithmetic number, because the mean of its divisors is an integer number (77572200615057).

Almost surely, 2155144401230113 is an apocalyptic number.

It is an amenable number.

155144401230113 is a deficient number, since it is larger than the sum of its proper divisors (1).

155144401230113 is an equidigital number, since it uses as much as digits as its factorization.

155144401230113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 155144401230113 its reverse (311032104441551), we get a palindrome (466176505671664).

The spelling of 155144401230113 in words is "one hundred fifty-five trillion, one hundred forty-four billion, four hundred one million, two hundred thirty thousand, one hundred thirteen".