Base | Representation |
---|---|
bin | 10110100101100111000… |
… | …011011011000011010101 |
3 | 12111101112022222212220022 |
4 | 112211213003123003111 |
5 | 200412412302104331 |
6 | 3145024301114525 |
7 | 220100156350505 |
oct | 26454703330325 |
9 | 5441468885808 |
10 | 1552212144341 |
11 | 549320320201 |
12 | 2109b4858a45 |
13 | b34b057a581 |
14 | 551adab9a05 |
15 | 2a59b05967b |
hex | 169670db0d5 |
1552212144341 has 2 divisors, whose sum is σ = 1552212144342. Its totient is φ = 1552212144340.
The previous prime is 1552212144337. The next prime is 1552212144389. The reversal of 1552212144341 is 1434412122551.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1197864580900 + 354347563441 = 1094470^2 + 595271^2 .
It is a cyclic number.
It is not a de Polignac number, because 1552212144341 - 22 = 1552212144337 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1552212144311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776106072170 + 776106072171.
It is an arithmetic number, because the mean of its divisors is an integer number (776106072171).
Almost surely, 21552212144341 is an apocalyptic number.
It is an amenable number.
1552212144341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1552212144341 is an equidigital number, since it uses as much as digits as its factorization.
1552212144341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 38400, while the sum is 35.
Adding to 1552212144341 its reverse (1434412122551), we get a palindrome (2986624266892).
The spelling of 1552212144341 in words is "one trillion, five hundred fifty-two billion, two hundred twelve million, one hundred forty-four thousand, three hundred forty-one".
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