Base | Representation |
---|---|
bin | 1001000010010010111… |
… | …1110001010011000111 |
3 | 112211200121122120211012 |
4 | 2100210233301103013 |
5 | 10020410220401002 |
6 | 155151503432435 |
7 | 14133606330551 |
oct | 2204457612307 |
9 | 484617576735 |
10 | 155235325127 |
11 | 5a920326433 |
12 | 26103bb571b |
13 | 1183c0b308c |
14 | 7728bcc4d1 |
15 | 408851bd52 |
hex | 2424bf14c7 |
155235325127 has 2 divisors, whose sum is σ = 155235325128. Its totient is φ = 155235325126.
The previous prime is 155235325039. The next prime is 155235325151. The reversal of 155235325127 is 721523532551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 155235325127 - 210 = 155235324103 is a prime.
It is a super-2 number, since 2×1552353251272 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155235325177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77617662563 + 77617662564.
It is an arithmetic number, because the mean of its divisors is an integer number (77617662564).
Almost surely, 2155235325127 is an apocalyptic number.
155235325127 is a deficient number, since it is larger than the sum of its proper divisors (1).
155235325127 is an equidigital number, since it uses as much as digits as its factorization.
155235325127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 315000, while the sum is 41.
Adding to 155235325127 its reverse (721523532551), we get a palindrome (876758857678).
The spelling of 155235325127 in words is "one hundred fifty-five billion, two hundred thirty-five million, three hundred twenty-five thousand, one hundred twenty-seven".
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