Base | Representation |
---|---|
bin | 10110100101110100111… |
… | …000110011100101111101 |
3 | 12111102010111201200110001 |
4 | 112211310320303211331 |
5 | 200413401211223201 |
6 | 3145103311514301 |
7 | 220106005222111 |
oct | 26456470634575 |
9 | 5442114650401 |
10 | 1552444242301 |
11 | 54942a3368a7 |
12 | 210a5a528991 |
13 | b3519692744 |
14 | 551d2855741 |
15 | 2a5b1604301 |
hex | 16974e3397d |
1552444242301 has 2 divisors, whose sum is σ = 1552444242302. Its totient is φ = 1552444242300.
The previous prime is 1552444242221. The next prime is 1552444242313. The reversal of 1552444242301 is 1032424442551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1453112113401 + 99332128900 = 1205451^2 + 315170^2 .
It is a cyclic number.
It is not a de Polignac number, because 1552444242301 - 213 = 1552444234109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1552444242341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776222121150 + 776222121151.
It is an arithmetic number, because the mean of its divisors is an integer number (776222121151).
Almost surely, 21552444242301 is an apocalyptic number.
It is an amenable number.
1552444242301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1552444242301 is an equidigital number, since it uses as much as digits as its factorization.
1552444242301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 1552444242301 its reverse (1032424442551), we get a palindrome (2584868684852).
The spelling of 1552444242301 in words is "one trillion, five hundred fifty-two billion, four hundred forty-four million, two hundred forty-two thousand, three hundred one".
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