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1552531130005 = 53139672524913
BaseRepresentation
bin10110100101111010000…
…100010000011010010101
312111102100120020000222011
4112211322010100122111
5200414040432130010
63145120054104221
7220111111603042
oct26457204203225
95442316200864
101552531130005
11549474391919
12210a8364b071
13b3531694b9b
14552001d21c9
152a5b9068a8a
hex1697a110695

1552531130005 has 16 divisors (see below), whose sum is σ = 1923620880384. Its totient is φ = 1201656119040.

The previous prime is 1552531129969. The next prime is 1552531130011. The reversal of 1552531130005 is 5000311352551.

It is a de Polignac number, because none of the positive numbers 2k-1552531130005 is a prime.

It is a super-2 number, since 2×15525311300052 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 647572 + ... + 1877341.

It is an arithmetic number, because the mean of its divisors is an integer number (120226305024).

Almost surely, 21552531130005 is an apocalyptic number.

It is an amenable number.

1552531130005 is a deficient number, since it is larger than the sum of its proper divisors (371089750379).

1552531130005 is a wasteful number, since it uses less digits than its factorization.

1552531130005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2528916.

The product of its (nonzero) digits is 11250, while the sum is 31.

Adding to 1552531130005 its reverse (5000311352551), we get a palindrome (6552842482556).

The spelling of 1552531130005 in words is "one trillion, five hundred fifty-two billion, five hundred thirty-one million, one hundred thirty thousand, five".

Divisors: 1 5 31 155 3967 19835 122977 614885 2524913 12624565 78272303 391361515 10016329871 50081649355 310506226001 1552531130005