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1553104117 is a prime number
BaseRepresentation
bin101110010010010…
…0111110011110101
311000020102212022201
41130210213303311
511140043312432
6414040224501
753326111225
oct13444476365
94006385281
101553104117
11727761124
1237416b131
131b99c6526
1410a3a8085
1591538ee7
hex5c927cf5

1553104117 has 2 divisors, whose sum is σ = 1553104118. Its totient is φ = 1553104116.

The previous prime is 1553104093. The next prime is 1553104121. The reversal of 1553104117 is 7114013551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1550311876 + 2792241 = 39374^2 + 1671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1553104117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1553114117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776552058 + 776552059.

It is an arithmetic number, because the mean of its divisors is an integer number (776552059).

Almost surely, 21553104117 is an apocalyptic number.

It is an amenable number.

1553104117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1553104117 is an equidigital number, since it uses as much as digits as its factorization.

1553104117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2100, while the sum is 28.

The square root of 1553104117 is about 39409.4419777799. The cubic root of 1553104117 is about 1158.0665664418.

Adding to 1553104117 its reverse (7114013551), we get a palindrome (8667117668).

The spelling of 1553104117 in words is "one billion, five hundred fifty-three million, one hundred four thousand, one hundred seventeen".