Base | Representation |
---|---|
bin | 10110100110100010000… |
… | …111101011000010001001 |
3 | 12111111002101200100212202 |
4 | 112212202013223002021 |
5 | 200421424444122441 |
6 | 3145310501045545 |
7 | 220133551431311 |
oct | 26464207530211 |
9 | 5444071610782 |
10 | 1553203114121 |
11 | 54978973649a |
12 | 2110306b68b5 |
13 | b360a975419 |
14 | 55265556441 |
15 | 2a60805519b |
hex | 169a21eb089 |
1553203114121 has 2 divisors, whose sum is σ = 1553203114122. Its totient is φ = 1553203114120.
The previous prime is 1553203114109. The next prime is 1553203114201. The reversal of 1553203114121 is 1214113023551.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1410726307600 + 142476806521 = 1187740^2 + 377461^2 .
It is a cyclic number.
It is not a de Polignac number, because 1553203114121 - 226 = 1553136005257 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1553203116121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776601557060 + 776601557061.
It is an arithmetic number, because the mean of its divisors is an integer number (776601557061).
Almost surely, 21553203114121 is an apocalyptic number.
It is an amenable number.
1553203114121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1553203114121 is an equidigital number, since it uses as much as digits as its factorization.
1553203114121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1553203114121 its reverse (1214113023551), we get a palindrome (2767316137672).
The spelling of 1553203114121 in words is "one trillion, five hundred fifty-three billion, two hundred three million, one hundred fourteen thousand, one hundred twenty-one".
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