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15532212145 = 53106442429
BaseRepresentation
bin11100111011100101…
…01011111110110001
31111002110121010111111
432131302223332301
5223302221242040
611045125113321
71056621424222
oct163562537661
944073533444
1015532212145
11665058a96a
123015858841
131606b9bc98
14a74ba3249
1560d8e1dea
hex39dcabfb1

15532212145 has 4 divisors (see below), whose sum is σ = 18638654580. Its totient is φ = 12425769712.

The previous prime is 15532212139. The next prime is 15532212209. The reversal of 15532212145 is 54121223551.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54121223551 = 311745845921.

It can be written as a sum of positive squares in 2 ways, for example, as 8088663969 + 7443548176 = 89937^2 + 86276^2 .

It is a cyclic number.

It is not a de Polignac number, because 15532212145 - 217 = 15532081073 is a prime.

It is a super-2 number, since 2×155322121452 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1553221210 + ... + 1553221219.

It is an arithmetic number, because the mean of its divisors is an integer number (4659663645).

Almost surely, 215532212145 is an apocalyptic number.

It is an amenable number.

15532212145 is a deficient number, since it is larger than the sum of its proper divisors (3106442435).

15532212145 is an equidigital number, since it uses as much as digits as its factorization.

15532212145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3106442434.

The product of its digits is 12000, while the sum is 31.

Adding to 15532212145 its reverse (54121223551), we get a palindrome (69653435696).

The spelling of 15532212145 in words is "fifteen billion, five hundred thirty-two million, two hundred twelve thousand, one hundred forty-five".

Divisors: 1 5 3106442429 15532212145