Base | Representation |
---|---|
bin | 100011010100100010110110… |
… | …110001001001110001000111 |
3 | 202101000200120200010102012012 |
4 | 203110202312301021301013 |
5 | 130330121333014000403 |
6 | 1310215443122444435 |
7 | 44502123226122665 |
oct | 4324426661116107 |
9 | 671020520112165 |
10 | 155343443500103 |
11 | 4555186a073711 |
12 | 1550a724b0371b |
13 | 688aa93057b51 |
14 | 2a5093c963c35 |
15 | 12e5c8d292ed8 |
hex | 8d48b6c49c47 |
155343443500103 has 2 divisors, whose sum is σ = 155343443500104. Its totient is φ = 155343443500102.
The previous prime is 155343443499973. The next prime is 155343443500117. The reversal of 155343443500103 is 301005344343551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 155343443500103 - 214 = 155343443483719 is a prime.
It is a super-2 number, since 2×1553434435001032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155343443503103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77671721750051 + 77671721750052.
It is an arithmetic number, because the mean of its divisors is an integer number (77671721750052).
Almost surely, 2155343443500103 is an apocalyptic number.
155343443500103 is a deficient number, since it is larger than the sum of its proper divisors (1).
155343443500103 is an equidigital number, since it uses as much as digits as its factorization.
155343443500103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 155343443500103 its reverse (301005344343551), we get a palindrome (456348787843654).
The spelling of 155343443500103 in words is "one hundred fifty-five trillion, three hundred forty-three billion, four hundred forty-three million, five hundred thousand, one hundred three".
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