Base | Representation |
---|---|
bin | 10110100111010100000… |
… | …001001001100101010101 |
3 | 12111120020201221001001112 |
4 | 112213110001021211111 |
5 | 200430133301440140 |
6 | 3145525524104405 |
7 | 220163365205462 |
oct | 26472401114525 |
9 | 5446221831045 |
10 | 1554040265045 |
11 | 54a079241364 |
12 | 211224b35105 |
13 | b37122350b8 |
14 | 553047d2669 |
15 | 2a6567b9c65 |
hex | 169d4049955 |
1554040265045 has 16 divisors (see below), whose sum is σ = 1872941745600. Its totient is φ = 1237846473600.
The previous prime is 1554040265027. The next prime is 1554040265087. The reversal of 1554040265045 is 5405620404551.
It is not a de Polignac number, because 1554040265045 - 26 = 1554040264981 is a prime.
It is a super-2 number, since 2×15540402650452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1554040264993 and 1554040265011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 642506 + ... + 1876404.
It is an arithmetic number, because the mean of its divisors is an integer number (117058859100).
Almost surely, 21554040265045 is an apocalyptic number.
It is an amenable number.
1554040265045 is a deficient number, since it is larger than the sum of its proper divisors (318901480555).
1554040265045 is a wasteful number, since it uses less digits than its factorization.
1554040265045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1234996.
The product of its (nonzero) digits is 480000, while the sum is 41.
Adding to 1554040265045 its reverse (5405620404551), we get a palindrome (6959660669596).
The spelling of 1554040265045 in words is "one trillion, five hundred fifty-four billion, forty million, two hundred sixty-five thousand, forty-five".
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