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15543150433133 is a prime number
BaseRepresentation
bin1110001000101110101111…
…1101011101001101101101
32001000220120212201012210012
43202023223331131031231
54014124333002330013
653020231424223005
73162645520535141
oct342135375351555
961026525635705
1015543150433133
114a528a4235064
1218b044976aa65
1388993602540b
143ba41486b221
151be4a663b1a8
hexe22ebf5d36d

15543150433133 has 2 divisors, whose sum is σ = 15543150433134. Its totient is φ = 15543150433132.

The previous prime is 15543150433127. The next prime is 15543150433159. The reversal of 15543150433133 is 33133405134551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10118080277449 + 5425070155684 = 3180893^2 + 2329178^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15543150433133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15543150433193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7771575216566 + 7771575216567.

It is an arithmetic number, because the mean of its divisors is an integer number (7771575216567).

Almost surely, 215543150433133 is an apocalyptic number.

It is an amenable number.

15543150433133 is a deficient number, since it is larger than the sum of its proper divisors (1).

15543150433133 is an equidigital number, since it uses as much as digits as its factorization.

15543150433133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 15543150433133 its reverse (33133405134551), we get a palindrome (48676555567684).

The spelling of 15543150433133 in words is "fifteen trillion, five hundred forty-three billion, one hundred fifty million, four hundred thirty-three thousand, one hundred thirty-three".