Base | Representation |
---|---|
bin | 11101000011110010… |
… | …00110111001010001 |
3 | 1111021021001010100011 |
4 | 32201321012321101 |
5 | 223422324112423 |
6 | 11100023354521 |
7 | 1061415230002 |
oct | 164171067121 |
9 | 44237033304 |
10 | 15601004113 |
11 | 66863a6332 |
12 | 30348b2a41 |
13 | 16182069a6 |
14 | a7dd8d1a9 |
15 | 61497eb0d |
hex | 3a1e46e51 |
15601004113 has 2 divisors, whose sum is σ = 15601004114. Its totient is φ = 15601004112.
The previous prime is 15601004039. The next prime is 15601004119. The reversal of 15601004113 is 31140010651.
15601004113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15423901249 + 177102864 = 124193^2 + 13308^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15601004113 is a prime.
It is not a weakly prime, because it can be changed into another prime (15601004119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7800502056 + 7800502057.
It is an arithmetic number, because the mean of its divisors is an integer number (7800502057).
Almost surely, 215601004113 is an apocalyptic number.
It is an amenable number.
15601004113 is a deficient number, since it is larger than the sum of its proper divisors (1).
15601004113 is an equidigital number, since it uses as much as digits as its factorization.
15601004113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 15601004113 its reverse (31140010651), we get a palindrome (46741014764).
The spelling of 15601004113 in words is "fifteen billion, six hundred one million, four thousand, one hundred thirteen".
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