15630601222141 has 4 divisors (see below), whose sum is σ = 15671842914400. Its totient is φ = 15589359529884.

The previous prime is 15630601222099. The next prime is 15630601222151. The reversal of 15630601222141 is 14122210603651.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15630601222141 - 2¹¹ = 15630601220093 is a prime.

It is a super-4 number, since 4×15630601222141⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15630601222097 and 15630601222106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15630601222151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20620845561 + ... + 20620846318.

It is an arithmetic number, because the mean of its divisors is an integer number (3917960728600).

Almost surely, 2^{15630601222141} is an apocalyptic number.

It is an amenable number.

15630601222141 is a deficient number, since it is larger than the sum of its proper divisors (41241692259).

15630601222141 is an equidigital number, since it uses as much as digits as its factorization.

15630601222141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41241692258.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 15630601222141 its reverse (14122210603651), we get a palindrome (29752811825792).

The spelling of 15630601222141 in words is "fifteen trillion, six hundred thirty billion, six hundred one million, two hundred twenty-two thousand, one hundred forty-one".