Base | Representation |
---|---|
bin | 100011101001110101010111… |
… | …101000111000011000000100 |
3 | 202120012112210210212012220020 |
4 | 203221311113220320120010 |
5 | 131023104032411003012 |
6 | 1313255514033335140 |
7 | 45012614355454203 |
oct | 4351652750703004 |
9 | 676175723765806 |
10 | 156806431344132 |
11 | 45a66263616449 |
12 | 157061787074b0 |
13 | 6965a2440843b |
14 | 2aa168678323a |
15 | 131dd660e7a8c |
hex | 8e9d57a38604 |
156806431344132 has 24 divisors (see below), whose sum is σ = 370893750852576. Its totient is φ = 51552799345728.
The previous prime is 156806431344097. The next prime is 156806431344139. The reversal of 156806431344132 is 231443134608651.
It is not an unprimeable number, because it can be changed into a prime (156806431344139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 89501386878 + ... + 89501388629.
It is an arithmetic number, because the mean of its divisors is an integer number (15453906285524).
Almost surely, 2156806431344132 is an apocalyptic number.
156806431344132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
156806431344132 is an abundant number, since it is smaller than the sum of its proper divisors (214087319508444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
156806431344132 is a wasteful number, since it uses less digits than its factorization.
156806431344132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179002775587 (or 179002775585 counting only the distinct ones).
The product of its (nonzero) digits is 4976640, while the sum is 51.
The spelling of 156806431344132 in words is "one hundred fifty-six trillion, eight hundred six billion, four hundred thirty-one million, three hundred forty-four thousand, one hundred thirty-two".
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