Base | Representation |
---|---|
bin | 11101010000000100… |
… | …11101101101010011 |
3 | 1111112110001221221112 |
4 | 32220002131231103 |
5 | 224130223321042 |
6 | 11114145443535 |
7 | 1064106550562 |
oct | 165002355523 |
9 | 44473057845 |
10 | 15704120147 |
11 | 67296259a1 |
12 | 30633405ab |
13 | 163369b8b1 |
14 | a8d951bd9 |
15 | 61da4c982 |
hex | 3a809db53 |
15704120147 has 2 divisors, whose sum is σ = 15704120148. Its totient is φ = 15704120146.
The previous prime is 15704120111. The next prime is 15704120167. The reversal of 15704120147 is 74102140751.
15704120147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15704120147 is a prime.
It is a super-2 number, since 2×157041201472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15704120167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7852060073 + 7852060074.
It is an arithmetic number, because the mean of its divisors is an integer number (7852060074).
Almost surely, 215704120147 is an apocalyptic number.
15704120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
15704120147 is an equidigital number, since it uses as much as digits as its factorization.
15704120147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7840, while the sum is 32.
Adding to 15704120147 its reverse (74102140751), we get a palindrome (89806260898).
The spelling of 15704120147 in words is "fifteen billion, seven hundred four million, one hundred twenty thousand, one hundred forty-seven".
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