Base | Representation |
---|---|
bin | 1110010011100110110100… |
… | …0100100100011001001111 |
3 | 2001200202212202102102001112 |
4 | 3210321231010210121033 |
5 | 4030210020014332033 |
6 | 53242132354202235 |
7 | 3212312032124414 |
oct | 344715504443117 |
9 | 61622782372045 |
10 | 15730000152143 |
11 | 5015068007542 |
12 | 19206b528337b |
13 | 8a1442aa5b24 |
14 | 3c549c26410b |
15 | 1c4290375c48 |
hex | e4e6d12464f |
15730000152143 has 2 divisors, whose sum is σ = 15730000152144. Its totient is φ = 15730000152142.
The previous prime is 15730000152101. The next prime is 15730000152197. The reversal of 15730000152143 is 34125100003751.
15730000152143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15730000152143 - 216 = 15730000086607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15730000152443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7865000076071 + 7865000076072.
It is an arithmetic number, because the mean of its divisors is an integer number (7865000076072).
Almost surely, 215730000152143 is an apocalyptic number.
15730000152143 is a deficient number, since it is larger than the sum of its proper divisors (1).
15730000152143 is an equidigital number, since it uses as much as digits as its factorization.
15730000152143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 32.
Adding to 15730000152143 its reverse (34125100003751), we get a palindrome (49855100155894).
The spelling of 15730000152143 in words is "fifteen trillion, seven hundred thirty billion, one hundred fifty-two thousand, one hundred forty-three".
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