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15980131159 = 63125325089
BaseRepresentation
bin11101110000111110…
…10111001101010111
31112020200102202212121
432320133113031113
5230211403144114
611201405400411
71104000605446
oct167037271527
945220382777
1015980131159
116860405073
12311b869107
13167891a715
14ab847cd5d
15637dbda24
hex3b87d7357

15980131159 has 4 divisors (see below), whose sum is σ = 16005456880. Its totient is φ = 15954805440.

The previous prime is 15980131129. The next prime is 15980131171. The reversal of 15980131159 is 95113108951.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 95113108951 = 713587586993.

It is a cyclic number.

It is not a de Polignac number, because 15980131159 - 215 = 15980098391 is a prime.

It is a super-3 number, since 3×159801311593 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15980131109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12661914 + ... + 12663175.

It is an arithmetic number, because the mean of its divisors is an integer number (4001364220).

Almost surely, 215980131159 is an apocalyptic number.

15980131159 is a deficient number, since it is larger than the sum of its proper divisors (25325721).

15980131159 is an equidigital number, since it uses as much as digits as its factorization.

15980131159 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25325720.

The product of its (nonzero) digits is 48600, while the sum is 43.

The spelling of 15980131159 in words is "fifteen billion, nine hundred eighty million, one hundred thirty-one thousand, one hundred fifty-nine".

Divisors: 1 631 25325089 15980131159