1600423412041 has 4 divisors (see below), whose sum is σ = 1612640384784. Its totient is φ = 1588206439300.

The previous prime is 1600423412017. The next prime is 1600423412089. The reversal of 1600423412041 is 1402143240061.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1600423412041 - 2¹³ = 1600423403849 is a prime.

It is a super-3 number, since 3×1600423412041³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1600423412011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6108486175 + ... + 6108486436.

It is an arithmetic number, because the mean of its divisors is an integer number (403160096196).

Almost surely, 2^{1600423412041} is an apocalyptic number.

It is an amenable number.

1600423412041 is a deficient number, since it is larger than the sum of its proper divisors (12216972743).

1600423412041 is a wasteful number, since it uses less digits than its factorization.

1600423412041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12216972742.

The product of its (nonzero) digits is 4608, while the sum is 28.

The spelling of 1600423412041 in words is "one trillion, six hundred billion, four hundred twenty-three million, four hundred twelve thousand, forty-one".