Base | Representation |
---|---|
bin | 1001010100001101011… |
… | …0110110100110000011 |
3 | 120022002201202011122222 |
4 | 2111003112312212003 |
5 | 10110232211313321 |
6 | 201304555121255 |
7 | 14364015213023 |
oct | 2250326664603 |
9 | 508081664588 |
10 | 160043854211 |
11 | 6196864650a |
12 | 2702644322b |
13 | 12127382867 |
14 | 7a6368ba83 |
15 | 426a7513ab |
hex | 25435b6983 |
160043854211 has 2 divisors, whose sum is σ = 160043854212. Its totient is φ = 160043854210.
The previous prime is 160043854183. The next prime is 160043854213. The reversal of 160043854211 is 112458340061.
It is a strong prime.
It is an emirp because it is prime and its reverse (112458340061) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 160043854211 - 210 = 160043853187 is a prime.
It is a super-2 number, since 2×1600438542112 (a number of 23 digits) contains 22 as substring.
Together with 160043854213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (160043854213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80021927105 + 80021927106.
It is an arithmetic number, because the mean of its divisors is an integer number (80021927106).
Almost surely, 2160043854211 is an apocalyptic number.
160043854211 is a deficient number, since it is larger than the sum of its proper divisors (1).
160043854211 is an equidigital number, since it uses as much as digits as its factorization.
160043854211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 35.
The spelling of 160043854211 in words is "one hundred sixty billion, forty-three million, eight hundred fifty-four thousand, two hundred eleven".
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