Base | Representation |
---|---|
bin | 1110100100000101100100… |
… | …1111110101001001001111 |
3 | 2002200211200221100100012100 |
4 | 3221001121033311021033 |
5 | 4044324400130322201 |
6 | 54020155521210143 |
7 | 3241624265052021 |
oct | 351013117651117 |
9 | 62624627310170 |
10 | 16013135401551 |
11 | 5114150522032 |
12 | 1967552790953 |
13 | 8c2055947272 |
14 | 3d507b652011 |
15 | 1cb812176886 |
hex | e90593f524f |
16013135401551 has 24 divisors (see below), whose sum is σ = 23307106927104. Its totient is φ = 10593724124880.
The previous prime is 16013135401537. The next prime is 16013135401561. The reversal of 16013135401551 is 15510453131061.
16013135401551 is a `hidden beast` number, since 1 + 6 + 0 + 1 + 31 + 35 + 40 + 1 + 551 = 666.
It is not a de Polignac number, because 16013135401551 - 27 = 16013135401423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16013135401561) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 80977540 + ... + 81175046.
It is an arithmetic number, because the mean of its divisors is an integer number (971129455296).
Almost surely, 216013135401551 is an apocalyptic number.
16013135401551 is a deficient number, since it is larger than the sum of its proper divisors (7293971525553).
16013135401551 is a wasteful number, since it uses less digits than its factorization.
16013135401551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266411 (or 266408 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 36.
The spelling of 16013135401551 in words is "sixteen trillion, thirteen billion, one hundred thirty-five million, four hundred one thousand, five hundred fifty-one".
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