Base | Representation |
---|---|
bin | 11101110111000010… |
… | …11100100010101101 |
3 | 1112101020011122001220 |
4 | 32323201130202231 |
5 | 230312414241231 |
6 | 11210424053553 |
7 | 1105156220253 |
oct | 167341344255 |
9 | 45336148056 |
10 | 16031008941 |
11 | 68870a5322 |
12 | 31349042b9 |
13 | 168632250c |
14 | ac11245d3 |
15 | 63c5bd896 |
hex | 3bb85c8ad |
16031008941 has 4 divisors (see below), whose sum is σ = 21374678592. Its totient is φ = 10687339292.
The previous prime is 16031008937. The next prime is 16031008949. The reversal of 16031008941 is 14980013061.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16031008941 - 22 = 16031008937 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16031008949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2671834821 + ... + 2671834826.
It is an arithmetic number, because the mean of its divisors is an integer number (5343669648).
Almost surely, 216031008941 is an apocalyptic number.
It is an amenable number.
16031008941 is a deficient number, since it is larger than the sum of its proper divisors (5343669651).
16031008941 is an equidigital number, since it uses as much as digits as its factorization.
16031008941 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5343669650.
The product of its (nonzero) digits is 5184, while the sum is 33.
The spelling of 16031008941 in words is "sixteen billion, thirty-one million, eight thousand, nine hundred forty-one".
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