Base | Representation |
---|---|
bin | 1110100101010011011011… |
… | …0111010011111101100101 |
3 | 2002202211122100120220121002 |
4 | 3221110312313103331211 |
5 | 4100200200021312232 |
6 | 54033533325403045 |
7 | 3243264203016263 |
oct | 351246667237545 |
9 | 62684570526532 |
10 | 16034033385317 |
11 | 5121aa49265a2 |
12 | 196b605409485 |
13 | 8c400639092c |
14 | 3d60a0ccb433 |
15 | 1cc136b71b62 |
hex | e9536dd3f65 |
16034033385317 has 2 divisors, whose sum is σ = 16034033385318. Its totient is φ = 16034033385316.
The previous prime is 16034033385269. The next prime is 16034033385323. The reversal of 16034033385317 is 71358333043061.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14421758164801 + 1612275220516 = 3797599^2 + 1269754^2 .
It is a cyclic number.
It is not a de Polignac number, because 16034033385317 - 210 = 16034033384293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16034033385397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8017016692658 + 8017016692659.
It is an arithmetic number, because the mean of its divisors is an integer number (8017016692659).
Almost surely, 216034033385317 is an apocalyptic number.
It is an amenable number.
16034033385317 is a deficient number, since it is larger than the sum of its proper divisors (1).
16034033385317 is an equidigital number, since it uses as much as digits as its factorization.
16034033385317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 47.
The spelling of 16034033385317 in words is "sixteen trillion, thirty-four billion, thirty-three million, three hundred eighty-five thousand, three hundred seventeen".
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