Base | Representation |
---|---|
bin | 1001010101101100001… |
… | …0010110100001110001 |
3 | 120100010102022000221110 |
4 | 2111123002112201301 |
5 | 10112040412230134 |
6 | 201412230143533 |
7 | 14406611062512 |
oct | 2253302264161 |
9 | 510112260843 |
10 | 160441133169 |
11 | 62051923029 |
12 | 271174b1ba9 |
13 | 1218b780775 |
14 | 7aa0344a09 |
15 | 42905787e9 |
hex | 255b096871 |
160441133169 has 4 divisors (see below), whose sum is σ = 213921510896. Its totient is φ = 106960755444.
The previous prime is 160441133161. The next prime is 160441133179. The reversal of 160441133169 is 961331144061.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 160441133169 - 23 = 160441133161 is a prime.
It is a super-2 number, since 2×1604411331692 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (160441133161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26740188859 + ... + 26740188864.
It is an arithmetic number, because the mean of its divisors is an integer number (53480377724).
Almost surely, 2160441133169 is an apocalyptic number.
It is an amenable number.
160441133169 is a deficient number, since it is larger than the sum of its proper divisors (53480377727).
160441133169 is an equidigital number, since it uses as much as digits as its factorization.
160441133169 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53480377726.
The product of its (nonzero) digits is 46656, while the sum is 39.
The spelling of 160441133169 in words is "one hundred sixty billion, four hundred forty-one million, one hundred thirty-three thousand, one hundred sixty-nine".
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