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16049351231 = 41391447591
BaseRepresentation
bin11101111001001110…
…11010101000111111
31112102111200111221222
432330213122220333
5230332113214411
611212321143555
71105501143314
oct167447325077
945374614858
1016049351231
116896493141
12313aa8abbb
13168a075244
14ac373ad0b
1563dee34db
hex3bc9daa3f

16049351231 has 4 divisors (see below), whose sum is σ = 16440798864. Its totient is φ = 15657903600.

The previous prime is 16049351209. The next prime is 16049351233. The reversal of 16049351231 is 13215394061.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16049351231 - 218 = 16049089087 is a prime.

It is a super-2 number, since 2×160493512312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16049351191 and 16049351200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16049351233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195723755 + ... + 195723836.

It is an arithmetic number, because the mean of its divisors is an integer number (4110199716).

Almost surely, 216049351231 is an apocalyptic number.

16049351231 is a deficient number, since it is larger than the sum of its proper divisors (391447633).

16049351231 is an equidigital number, since it uses as much as digits as its factorization.

16049351231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 391447632.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 16049351231 in words is "sixteen billion, forty-nine million, three hundred fifty-one thousand, two hundred thirty-one".

Divisors: 1 41 391447591 16049351231