Base | Representation |
---|---|
bin | 11101111001001110… |
… | …11110000001101001 |
3 | 1112102111201012222112 |
4 | 32330213132001221 |
5 | 230332114140342 |
6 | 11212321332105 |
7 | 1105501231613 |
oct | 167447360151 |
9 | 45374635875 |
10 | 16049365097 |
11 | 68964a25a7 |
12 | 313aa97035 |
13 | 168a07b64c |
14 | ac3741db3 |
15 | 63dee7682 |
hex | 3bc9de069 |
16049365097 has 2 divisors, whose sum is σ = 16049365098. Its totient is φ = 16049365096.
The previous prime is 16049365093. The next prime is 16049365099. The reversal of 16049365097 is 79056394061.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8299027801 + 7750337296 = 91099^2 + 88036^2 .
It is an emirp because it is prime and its reverse (79056394061) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16049365097 - 22 = 16049365093 is a prime.
Together with 16049365099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (16049365093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8024682548 + 8024682549.
It is an arithmetic number, because the mean of its divisors is an integer number (8024682549).
Almost surely, 216049365097 is an apocalyptic number.
It is an amenable number.
16049365097 is a deficient number, since it is larger than the sum of its proper divisors (1).
16049365097 is an equidigital number, since it uses as much as digits as its factorization.
16049365097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1224720, while the sum is 50.
The spelling of 16049365097 in words is "sixteen billion, forty-nine million, three hundred sixty-five thousand, ninety-seven".
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