16053725043331 has 4 divisors (see below), whose sum is σ = 16099203018312. Its totient is φ = 16008247068352.

The previous prime is 16053725043313. The next prime is 16053725043397. The reversal of 16053725043331 is 13334052735061.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16053725043331 - 2¹⁷ = 16053724912259 is a prime.

It is a super-3 number, since 3×16053725043331³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16053725041331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22738986961 + ... + 22738987666.

It is an arithmetic number, because the mean of its divisors is an integer number (4024800754578).

Almost surely, 2^{16053725043331} is an apocalyptic number.

16053725043331 is a deficient number, since it is larger than the sum of its proper divisors (45477974981).

16053725043331 is an equidigital number, since it uses as much as digits as its factorization.

16053725043331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45477974980.

The product of its (nonzero) digits is 680400, while the sum is 43.

Adding to 16053725043331 its reverse (13334052735061), we get a palindrome (29387777778392).

The spelling of 16053725043331 in words is "sixteen trillion, fifty-three billion, seven hundred twenty-five million, forty-three thousand, three hundred thirty-one".