Base | Representation |
---|---|
bin | 1110100110100111111110… |
… | …0100011100000100000101 |
3 | 2002212000012222112100101112 |
4 | 3221221333210130010011 |
5 | 4101033134332323023 |
6 | 54052205314134405 |
7 | 3245026455113624 |
oct | 351517744340405 |
9 | 62760188470345 |
10 | 16056728011013 |
11 | 51306904007a8 |
12 | 1973a99881405 |
13 | 8c61b20bca31 |
14 | 3d72150076bb |
15 | 1cca14260478 |
hex | e9a7f91c105 |
16056728011013 has 2 divisors, whose sum is σ = 16056728011014. Its totient is φ = 16056728011012.
The previous prime is 16056728010997. The next prime is 16056728011033. The reversal of 16056728011013 is 31011082765061.
16056728011013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9237119583169 + 6819608427844 = 3039263^2 + 2611438^2 .
It is a cyclic number.
It is not a de Polignac number, because 16056728011013 - 24 = 16056728010997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16056728011033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8028364005506 + 8028364005507.
It is an arithmetic number, because the mean of its divisors is an integer number (8028364005507).
Almost surely, 216056728011013 is an apocalyptic number.
It is an amenable number.
16056728011013 is a deficient number, since it is larger than the sum of its proper divisors (1).
16056728011013 is an equidigital number, since it uses as much as digits as its factorization.
16056728011013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 16056728011013 in words is "sixteen trillion, fifty-six billion, seven hundred twenty-eight million, eleven thousand, thirteen".
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